4x^2-7x+28=0

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Solution for 4x^2-7x+28=0 equation:


Simplifying
4x2 + -7x + 28 = 0

Reorder the terms:
28 + -7x + 4x2 = 0

Solving
28 + -7x + 4x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
7 + -1.75x + x2 = 0

Move the constant term to the right:

Add '-7' to each side of the equation.
7 + -1.75x + -7 + x2 = 0 + -7

Reorder the terms:
7 + -7 + -1.75x + x2 = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -1.75x + x2 = 0 + -7
-1.75x + x2 = 0 + -7

Combine like terms: 0 + -7 = -7
-1.75x + x2 = -7

The x term is -1.75x.  Take half its coefficient (-0.875).
Square it (0.765625) and add it to both sides.

Add '0.765625' to each side of the equation.
-1.75x + 0.765625 + x2 = -7 + 0.765625

Reorder the terms:
0.765625 + -1.75x + x2 = -7 + 0.765625

Combine like terms: -7 + 0.765625 = -6.234375
0.765625 + -1.75x + x2 = -6.234375

Factor a perfect square on the left side:
(x + -0.875)(x + -0.875) = -6.234375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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